Immersion Cooling Heat Rejection Capacity
Determine how much IT heat an immersion cooling system can remove by combining coolant flow, fluid properties, and the planned temperature rise.
Engineering planning aid—validate fluid property assumptions and exchanger performance with commissioning data before final design decisions.
Examples
- 420 L/min flow, 1,650 kg/m^3 density, 1.70 kJ/kg·K specific heat, 7 °C rise, 95% effectiveness ⇒ Heat rejection capacity: 130.57 kW.
- 180 L/min flow, 1,000 kg/m^3 density, 4.18 kJ/kg·K specific heat, 5 °C rise, effectiveness left blank ⇒ Heat rejection capacity: 59.56 kW.
FAQ
How should I choose the fluid density and specific heat inputs?
Use laboratory data or OEM datasheets at the operating temperature. Many hydrocarbon dielectric fluids sit between 1,650 and 1,800 kg/m^3 with specific heat near 1.6–1.9 kJ/kg·K.
What if the loop includes multiple tanks with different flows?
Aggregate the total effective flow rate across all tanks or compute each tank separately and sum their heat capacities before comparing with IT load.
Does the calculator include pump power penalties?
No. The result reflects thermal capacity only. Add pump power to your facility energy model when analysing efficiency or cost impacts.
Can I model staged heat exchangers with different effectiveness values?
Estimate a blended effectiveness by weighting each stage’s temperature approach by its share of the mass flow, or run the calculator for each stage and sum the delivered kW.
Additional Information
- Result unit: kilowatts of thermal load the immersion loop can reject under the stated conditions.
- Flow rate is converted from litres per minute to cubic metres per second before multiplying by density.
- Effectiveness defaults to 95% to account for exchanger and distribution losses when left blank.